Physics, asked by galaxy14, 6 months ago

an object suspended by a wire stretches out by 10mm. when object is immersed in a liquid the elongation in wire reduces by 10/3 mm. The ratio of the relative densities of the object and liquid is

a. 3:1 b. 1:3 c. 1:2 d. 2:1​

Answers

Answered by sarthakkkkkkkkk
1

Answer:

Explanation:

Young Modulus of Elasticity

Y=  

Al

FL

​  

 

F=  

L

YAl

​  

 

F=  

2

2×10  

11

×1×10  

−6

×10  

−3

×10  

−1

 

​  

 

F=100N

Work Done =  

2

1

​  

×100×1×10  

−3

×10  

−1

 

=0.005J

Work done = 5×10  

−3

joule

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