Science, asked by jatinbansode358, 8 months ago

An object takers second to reach the
ground from a hight of 5 m on a
planet. What is the value of 9 on
the planet ?​

Answers

Answered by 1105salonikumari
2

Explanation:

Time taken =5

Displacement=5m

u=0m/s

Let acceleration bem/s^2

s=ut+(1/2)at^2

therefore

5=(0) (5)+(1/2)(a)(5^2)

a*25/2=5

a=10/25

a=2/5

a=0.4

Answered by mohithvakada009
0

Answer:

0.4m/sec

Explanation:

u= 0m/s , s or h =5m, t= 1sec , g=?

apply formula s/h = 1/2gt²

do it ☺️

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