An object takers second to reach the
ground from a hight of 5 m on a
planet. What is the value of 9 on
the planet ?
Answers
Answered by
2
Explanation:
Time taken =5
Displacement=5m
u=0m/s
Let acceleration bem/s^2
s=ut+(1/2)at^2
therefore
5=(0) (5)+(1/2)(a)(5^2)
a*25/2=5
a=10/25
a=2/5
a=0.4
Answered by
0
Answer:
0.4m/sec
Explanation:
u= 0m/s , s or h =5m, t= 1sec , g=?
apply formula s/h = 1/2gt²
do it ☺️
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