Question

An object takers second to reach the
ground from a hight of 5 m on a
planet. What is the value of 9 on
the planet ?​

Answer 1

Explanation:

Time taken =5

Displacement=5m

u=0m/s

Let acceleration bem/s^2

s=ut+(1/2)at^2

therefore

5=(0) (5)+(1/2)(a)(5^2)

a*25/2=5

a=10/25

a=2/5

a=0.4

Answer 2

Answer:

0.4m/sec

Explanation:

u= 0m/s , s or h =5m, t= 1sec , g=?

apply formula s/h = 1/2gt²

do it ☺️