An object takes 10 seconds to reach the ground from a height of 10 m on a planet. What is the value of g on the earth.
use: s = ut + 1/2 gt^2
Answers
Answer:
the whole senario is something like this :
u= 0m/s
t= 10 sec
s= 10m
hence,
by second equation of motion which is also given in question
we have ,,
10 = 0*t + 1/2 g * 10^2
10 = 1/2 * 10 *10 *g
g= 10 / 50
g= 1/5
g= 0.2 m/s^2
Explanation:
Answer:
Time taken, t = 5 seconds
Displacement, s = 5 metres
Initial velocity, u = 0 metres/second
Let the acceleration be a m/s2 .
When the acceleration is constant, initial velocity, acceleration, time taken and displacement are related by a simple formula:
s=ut+(1/2)at2
Therefore,
5=(0)(5)+(1/2)(a)(52)
a×(25/2)=5
a=5/(25/2)
a=10/25
a=2/5
a=0.4
Therefore, the acceleration is 0.4m/s2 .
This is the acceleration due to gravity on that planet.
Please note that you can't call ‘acceleration due to gravity’ as ‘gravity’.
Gravity refers to gravitational force. Gravitational force (gravity) due to the planet on any mass ‘m’ (expressed in kilograms) = (0.4×m) newtons