Question

An object takes 4s to reach the ground from a height of 6m on a planet. What is the acceleration due to gravity on earth ?​

Answer 1

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✮ Given :-

• Initial velocity (u) = 0m/s
• Time taken (t) = 4s
• Height (h) = 6m

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✥ Need To Find :-

• Acceleration due to gravity (g)

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❂ Applied Formula :-

$\rm{h = ut + \dfrac{1}{2}\times gt^2}$

• h = height
• u = initial velocity
• t = time

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❁ Solution :-

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⠀⠀⠀⠀➜ ⠀h = ut + ½ × gt²

⠀⠀⠀⠀➜⠀ 6 = 0 × 4 + ½ × g × 4²

⠀⠀⠀⠀➜⠀ 6 = 0 + ½ × g × 16

⠀⠀⠀⠀➜⠀ 6 = g × 8

⠀⠀⠀⠀➜⠀ 6 = 8g

⠀⠀⠀⠀➜⠀ 8g = 6

⠀⠀⠀⠀➜⠀ g = ¾

⠀⠀⠀⠀➜ ⠀g = 0.75m/s²

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❆ Acceleration due to gravity is 0.75m/s²