Question

An object takes 5 seconds to reach the ground from a height of 25 m on a planet. What is the value of 'g' on that planet? ​

Answer 1

Explanation:

Here,

u=0

t=5 s

h= 25 m

Using second equation of motion,

s=ut+ 1/2 at ^2

5=(0*5) + 1/2(2*5^2)

=>g=5

Note: Before working out the sum find the value of acceleration using formula(s=ut+0.5at^2)

Answer 2

Answer:-

Here u = 0

S= 5m

t = 5s

From second equation of motion we have ,

$s \: = \: ut + \frac{1}{2} {gt}^{2}$

$5\: = \frac{1}{2}g( {5})^{2}$

$g \: = \frac{10}{25} = 0.4 {ms}^{2}$

Hence , the value of g on planet is 0.4m/s².