An object takes 5s to reach the ground from a height of 5m on a planet.What is the value of g on the planet?
Answers
Answered by
11
h=5m t=5s u=0 g=?
h =ut +1/2gt^2
5=0×5+1/2×5×5×g
1=5/2g
g=2/5 =0.4 m/s^2
h =ut +1/2gt^2
5=0×5+1/2×5×5×g
1=5/2g
g=2/5 =0.4 m/s^2
sakib1061:
^2 means
Answered by
16
Hi mate !!
Here's the answer !!
Given :
Time = 5 seconds
Height = 5 meters
To find :
Gravity = ?
Proof :
We know the formula that,
[tex]Height = ut + \frac{1}{2} gt^{2} [/tex]
Here,
H = Height , U = Initial Velocity , G = Gravity , T = Time
We know that,
Height = 5 meters
Initial Velocity = 0 m/sec ( As it is from rest )
G = ?
Time = 5 seconds
Substituting in the formula we get,
= 5 m = 0 × 5 + 1 / 2 × g × ( 5 )²
= 5 m = 0 + 1 / 2 × g × 25
= 5 m = 25 / 2 × g
=> g = 5 × 2 / 25
=> g = 10 / 25 = 0.4 m / sec ²
Hope my answer helped !!
Cheers !!
Here's the answer !!
Given :
Time = 5 seconds
Height = 5 meters
To find :
Gravity = ?
Proof :
We know the formula that,
[tex]Height = ut + \frac{1}{2} gt^{2} [/tex]
Here,
H = Height , U = Initial Velocity , G = Gravity , T = Time
We know that,
Height = 5 meters
Initial Velocity = 0 m/sec ( As it is from rest )
G = ?
Time = 5 seconds
Substituting in the formula we get,
= 5 m = 0 × 5 + 1 / 2 × g × ( 5 )²
= 5 m = 0 + 1 / 2 × g × 25
= 5 m = 25 / 2 × g
=> g = 5 × 2 / 25
=> g = 10 / 25 = 0.4 m / sec ²
Hope my answer helped !!
Cheers !!
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