Question

An object takes 7 s to reach ground from a height of 4 m on a planet.what is a value of g on that planet.
(answer in steps )​

Answer 1

Answer:

The gravitational acceleration of the planet = $\frac{8}{49}m/sec^2$

Explanation:

Let g be the gravitational acceleration on that planet.

We know

$S=ut+\frac{1}{2}gt^2, where\rightarrow u=0( As the object is starting from rest )\\\\S=4m, t=7sec\\\\\therefore 4=\frac{1}{2}g*7^2\\\\\implies g=\frac{8}{49}m/s^2$