an object throw vertically upwards reaches a height of 500m what was its initial velocity how long will the object take to come back to the earth assume g=10 m/s square
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Given,
u (initial velocity) = u
v (final velocity) = 0 (as the body is thrown vertically upward)
h (distance travelled) = 500m
t (time of flight) = t
g (gravitational accl'n)=10 m/s^2
From the equations of motion,
(a) h = u^2 / 2g
=> h * 2g = u^2
=> 500 * 2(10) = u^2
=> 500 * 20 = u^2
=> 10000 = u^2
u = 100 m/s
(b) t = 2u / g
=> t = 2(100) / 10
t = 20 s
u (initial velocity) = u
v (final velocity) = 0 (as the body is thrown vertically upward)
h (distance travelled) = 500m
t (time of flight) = t
g (gravitational accl'n)=10 m/s^2
From the equations of motion,
(a) h = u^2 / 2g
=> h * 2g = u^2
=> 500 * 2(10) = u^2
=> 500 * 20 = u^2
=> 10000 = u^2
u = 100 m/s
(b) t = 2u / g
=> t = 2(100) / 10
t = 20 s
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