Question

An object thrown from ground level at velocity 60m/s making and launch angle of 30 degree find the range of projectile ( Ans. 324 m I need the the method only)​

Answer 1

Answer:

Given

angle of projection = 30 degrees

initial velocity (u) = 60 m/s

$during \: the \: time \: offlight \: \\ vertical \: displacement \: is \: 0 \\ 0 = u \sin( \theta )t + \frac{1}{2}g {t}^{2} \\ t = \frac{2u \sin( \theta ) }{g} \\ time \: of \: flight \: = \frac{2u \sin( \theta) }{g} \\t = \frac{2(60)( \sin( {30}^{0}) ) }{10} \\ t = 6s \\ range \: = u \cos( \theta )t \\ r = 60( \cos( {30}^{0} )) 6 \\ r = 360 \times \frac{ \sqrt{3} }{2} \\ r = 180 \times 1.732 \\ r = 324m \: (approx)$