Question

an object thrown upward reaches the highest point in 5second find the velocity with which it was thrown also find the distance covered​?

Answer 1

t=5

for upward motion

v=0 at max height

a=g=-10m/s

v=u+gt

0=u+5*-10

u=50m/s

distance covered till max height=

v^2=u^2+2as

0=2500-20s

s=2500/20=125m