an object thrown upwards reaches the highest point in 5 sec,find the velocity with which it was thrown.also find the distance covered.with formulas
amrtanshu10Amrtanshu:
what is the value of g? Is it 9.8 or 10
not goven
given
its 9.81...... but for convinience we take it as 10 or 9.8 according to question
That we know but I am asking acording to the question what shld I use
I'll try with 10
okay
semd me the answer plz
i posted the answe
answer*
Answers
Answered by
62
time taken(t)= 5seconds
at highest point velocity is 0
so final velocity(v) = 0
acceleration due to gravity(g)= -9.8
negative because force is in opposite direction
we need to find initial velocity(u)
we know v=u+at
on substituting values
0=u+9.8*5
so u = 9.8*5 = 49m/s
distance(s)= ut+1/2at^{2}
so,
s=5*49+1/2*9.8*5*5
on calculating u will get answer
at highest point velocity is 0
so final velocity(v) = 0
acceleration due to gravity(g)= -9.8
negative because force is in opposite direction
we need to find initial velocity(u)
we know v=u+at
on substituting values
0=u+9.8*5
so u = 9.8*5 = 49m/s
distance(s)= ut+1/2at^{2}
so,
s=5*49+1/2*9.8*5*5
on calculating u will get answer
Answered by
66
time taken = 5 sec
final velocity = 0
(g) = -9.8
v = u + at
0 = u + 9.8 ×5
u = 9.8 ×5
49 m/s = initial velocity
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