Physics, asked by adityashahi88, 1 year ago

an object thrown upwards reaches the highest point in 5 sec,find the velocity with which it was thrown.also find the distance covered.with formulas

amrtanshu10Amrtanshu: what is the value of g? Is it 9.8 or 10

adityashahi88: not goven

adityashahi88: given

prashant14400: its 9.81...... but for convinience we take it as 10 or 9.8 according to question

amrtanshu10Amrtanshu: That we know but I am asking acording to the question what shld I use

amrtanshu10Amrtanshu: I'll try with 10

adityashahi88: okay

adityashahi88: semd me the answer plz

prashant14400: i posted the answe

prashant14400: answer*

Answers

Answered by prashant14400

time taken(t)= 5seconds
at highest point velocity is 0
so final velocity(v) = 0
acceleration due to gravity(g)= -9.8
negative because force is in opposite direction
we need to find initial velocity(u)
we know v=u+at
on substituting values
0=u+9.8*5
so u = 9.8*5 = 49m/s

distance(s)= ut+1/2at^{2}
so,
s=5*49+1/2*9.8*5*5
on calculating u will get answer

Answered by Anonymous

time taken = 5 sec

final velocity = 0

(g) = -9.8

v = u + at

0 = u + 9.8 ×5

u = 9.8 ×5

49 m/s = initial velocity

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