Question

An object thrown vertically up from the ground passes the height 5m twice in an interval of 10s.what is the time of flight​

Answer 1

Answer:

The object has flight height (s−5) m in

2

10

s= 5s

The object is descending at the same time= 5s

Using,

s=ut+

2

1

at

2

s−5=0×5+

2

1

×9.8×5

2

s=127.5 m

Time taken to travel vertically 127.5 m,

=>127.5=0×t+

2

1

×9.8×t

2

t

2

=26.02s

t= 5.1 s

Therefore total time of flight is= 2×5.1 = 10.2s

104

s

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