Question

An object thrown vertically upward reaches a height of 320m.
What was it's initial velocity? How long will the object take to come back to the earth? Assume g=10m/s^2.​

Answer 1

Answer:

《ANSWER》

Let the initial velocity = u

final velocity = v

v= 0 m/s

s = 500 m 

2gs = v2−u2

2 (-10) 500 = u2

u = 100 m/s

v = u + at

0 = 100 - 10 t

t = 10 s

total time taken = 20 sec.

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Explanation:

BY - JANNAT

Answer 2

Given that,

height = 320 m,

final velocity = v = 0 [ object thrown vertically upward ]

- g = -10m/s² [ object thrown vertically upward ]

From, v² - u² = 2gh we can find the value of u

0 - u² = 2 × (-10) × 320

=> - u² = - 6400

$u \: = \: \sqrt{6400} = 80$

From, v = u + gt we can find the value of t

0 = 80 + (-10) × t

=> 0 = 80 -10t

=> 10t = 80

=> t = 8

Initial velocity = 80m/s

Time taken to come back to earth = 8×2 = 16 seconds