Question

an object thrown vertically upward reaches a height of 500 what is initial velocity how long will the object take to come back to the earth assume G is equal to 10 m s square​

Answer 1

Answer:

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Explanation:

v^2 - u^2 = 2as

0-u^2 = 2 × 10 × 500

-u^2 = 10000

u = -1000m/s

v-u=at

(v-u)/a=t

(0-(-100)) / 10=t

10 seconds = time

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