Question

An object thrown vertically upward reaches a height of 500 m what was its initial velocity

Answer 1

Let the initial velocity be u.

Distance traveled=500m

Acceleration=-9.8m/s^2

we know,

v^2=u^2+2as

0=u^2+2as

u^2=-2as

u^2=-2*(-9.8)*500

u^2=9800

u=70√(2)

u=98.98 m/s