Question

An object thrown vertically upwards reaches at maximum height in 5 sec .what is the velocity with which it was throw


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Answer 1

Answer:

answer in attachment

Answer 2

Here are the two equations you should use to solve this. First vf=vi +a*t, where vf is final velocity (what’s that at the end of going up?), vi is initial velocity, a= guess what, and t=the thing in question. Substitute the right values and solve for t.

I assume that when you ask how will it rise you do not mean like “blessed is he who sits on a tack, for he shall rise”, but you mean “how high will it rise? “

For that you need this equation: d= t*(vf +vi) /2, where d is the vertical distance, and you should already have the other variables. Now, if you’re still interested, compute!
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