an object thrown vertically upwards reaches the height of 500 metre full stop what was its initial velocity? How long will the object take to come back on the earth? Assume g=10 M per second
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Answered by
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Howdy!!
your answer is ---
Given , height h = 500m
according to formula--
v^2 - u^2 = 2gh
=> 0 - u^2 = 2×10s
=> u^2 = 20× 500
=> u = √10000
=> u = 100 m/s
Let, object take t time come back
according to formula ---
v = u +at
=> 0 = 100+ 10t
=> t = -10sec
it means it take 10 second to come back
hope it help you
your answer is ---
Given , height h = 500m
according to formula--
v^2 - u^2 = 2gh
=> 0 - u^2 = 2×10s
=> u^2 = 20× 500
=> u = √10000
=> u = 100 m/s
Let, object take t time come back
according to formula ---
v = u +at
=> 0 = 100+ 10t
=> t = -10sec
it means it take 10 second to come back
hope it help you
Krishna2492003:
it is incorrect the it will take 20 seconds to come back
Answered by
0
Answer:
Hope this will help you.
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