Question

an object thrown vertically upwards with speed 49 ms-1 and how long does it take to complete upward Journey what maximum height does it achieve

Answer 1

Answer:

Given,

u=49 m/s

g or a= 9.8 m/s^2

v=0 m/s.

then,

we know that,

v=u+at

t=u/a

49/9.8

t=5 seconds

we know that

v^2-u^2=2as

s or height=u^2/2g

49*5/2

height =122.5m.

Please mark it as brainliest.

Answer 2

Answer:

height =120.05 , time = 4.9 seconds

Explanation:

solution is in the attachment