Question

An object thrown vertically upwords reaches a height of 700 m . What was it’s

initial velocity ? How long will the object take to come back to the earth ?

Assuming g = 10 m / s²

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Answer 1

Explanation:

v^2 - u^2=2gs

0-u^2=2×(-10)×700

u=140m/s

v=u+at

0=140-10t

10t=140m/s

t=14s

Thus the 14s is required the object to reach from the ground 700m height the same 14s will be required by the object to reach the ground. Thus the total time taken to reach the ground will be 28s.