Question

An object travel towards east for 6m, then move towards north for 8m. Find its

distance covered and it’s displacement​

Answer 1

Given :- An object travel towards east for 6m, then move towards north for 8m. Find its distance covered and it’s displacement .

Solution :-

Let is assume that, initial position is A .

so, from A he travel towards east for 6m and reach at B .

• A - - - - - - B .

now, from B he move towards north for 8m and reach at C .

A - - - - - - B

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C (Final position.)

then,

→ Total distance covered = AB + BC = 6 + 8 = 14 m (Ans.)

and,

→ Total displacement = shortest path between initial position A and final position B .

therefore,

→ Total displacement = √(AB² + BC²) { using pythagoras theorem.}

→ Total displacement = √(6² + 8²)

→ Total displacement = √(36 + 64)

→ Total displacement = √100

→ Total displacement = 10 m (Ans.)

[ Note :- when we move in backward direction value of displacement can be negative also. ]

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Answer 2

Given : An object travel towards east for 6m, then move towards north for 8m.

To Find :  distance covered displacement​

Solution:

              NORTH

 WEST                EAST

            SOUTH

 EAST  = 6 m

 NORTH = 8 m

Distance = 6 + 8  = 14 m

Displacement = Final position - Initial Position

East taken on  + x  and  North on +y  and initial position at origin

Initial position = ( 0 , 0)

Final position    = ( 6 , 8 )    

Displacement = √(6 - 0)² + (8 - 0)²   = 10  m

distance covered = 104 m

displacement​ = 10 m

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