An object travelled from p to R through Q at uniform speed travel time is 10 seconds. observe to the given diagram and write down the answers to the question
Answers
Answered by
0
Answer:
Magnitude of area under the v−t graph gives the distance travelled by the body.
For 0≤t≤4 s :
Displacement S
1
= Area =
2
1
×(20+40)×2+
2
1
×(1+2)×20=90 m
For 4≤t≤5 s :
Displacement S
2
= Area =
2
1
×1×20=10 m
Total distance d=S
1
+S
2
=90+10=100 m
Option A is correct.
Similar questions