An object travelling along a straight path covers 35 m distance in 4 seconds. In next 6
seconds, it covers 50 m distance. What is the average speed of the object?
(1) 3.5 m/s (2) 4.5 m/s (3) 7.5 m/s (4) 8.5 m/s
Answers
Answered by
1
Answer:
option 4) is correct 8.5m/s
Explanation:
We have
average velocity= Total distance/total time
= (35m+50m)/ (4s+6s)
= 85m/10s
= 8.5m/s
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Answered by
2
Given,
- An object travelling along a straight path covers 35 m distance in 4 seconds. In next 6 seconds, it covers 50 m distance. What is the average speed of the object
To Find,
- Average speed
Answer :-
- According to the question
it is given that,
- Distance covered in 1st case, d¹ = 35m
- Time taken in 1st case, t¹ = 4s
- Distance covered in 2nd case, d² = 50m
- Time taken in 2nd case, t² = 6
we have to calculate average speed of the object
Average speed is calculated by the sum of total distance covered divided by the total time taken
- Average speed = total distance / total time taken
substitute the value we get
- Average speed = d¹ + d² / t¹ + t²
- " " = 35 + 50 /4 + 6
- " " = 85 /10
- Average speed = 8.5 m/s
Hence, the average speed of the object is 8.5 m/s
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