Question

An object travelling along a straight path covers 35 m distance in 4 seconds. In next 6
seconds, it covers 50 m distance. What is the average speed of the object?
(1) 3.5 m/s (2) 4.5 m/s (3) 7.5 m/s (4) 8.5 m/s

Answer 1

Given:-

• An object travelling along a straight path covers 35 m distance in 4 seconds. In next 6 seconds, it covers 50 m distance. What is the average speed of the object.

To Find :-

• Average Speed ?

Answer:-

According to the Question

It is given that ,

• Distance covered in 1st case,d¹ = 35 m

• Time taken in 1st case,t¹ = 4s

• Distance covered in 2nd case, d² = 50m

• Time taken in 2nd case, t² = 6

We have to calculate the average Speed of the object .

Average speed is calculated by the sum of total distance covered divided by total time taken .

• Av Speed = Total Distance / Total Time taken

Substitute the value we get

$:\implies$ Av Speed = d¹+d²/t¹ + t²

$:\implies$ Av. Speed = 35+50/4+6

$:\implies$ Av.Speed = 85/10

$:\implies$ Av Speed = 8.5m/s

• Hence, the average Speed of the object is 8.5m/s

So the required option is (8) 8.5m/s.

Answer 2

Given :-

An bject travelling along a straight path covers 35 m distance in 4 seconds. In next 6  seconds, it covers 50 m distance.

To Find :-

Average speed

Solution :-

Finding total distance covered

Distance covered = 35 + 50

Distance covered = 85 m

Now

Total time taken = 4 + 6

Total time taken = 10 sec

Now

Speed = Distance/Speed

Speed = 85/10

Speed = 8.5 m/s

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