Question

An object travelling along a straight path covers 35 m distance in 4 seconds. In next 6 seconds, it covers 50 m distance. What is the average speed of the object? (1) 3.5 m/s (2) 4.5 m/s (3) 7.5 m/s (4) 8.5 m/s​

Answer 1

${\large{\bf{\red{\underline{Given :}}}}}$

An object travelling along a straight path covers 35 m distance in 4 seconds. In next 6 seconds, it covers 50 m distance.

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${\large{\bf{\blue{\underline{To Find :}}}}}$

What is the average speed of object.

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${\large{\bf{\orange{\underline{Solution :}}}}}$

${\bigstar{\pink{\boxed{\mathfrak{Average \: speed = \frac{total \: distance \: covered}{total \: time \: taken} }}}}}$

Average speed of object :

${\sf{\purple{= \frac{35 + 50}{4 + 6} }}}$

${\sf{\purple{= {\cancel \frac{85}{10 } }}}}$

= 8.5m/s

So,

The average speed of object is 8.5m/s.

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${\bf{\underline{\fcolorbox{green}{red}{\blue{itzNobita5}}}}}$

Answer 2

Answer :-

Average speed of the object is 8.5 m/s [Option.4] .

Explanation :-

We have :-

→ 1st time = 4 sec

→ Distance covered in 1st time = 35 m

→ 2nd time = 6 sec

→ Distance covered in 2nd time = 50 m

To find :-

→ Average speed .

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For calculation of average speed, firstly we have to calculate the total distance covered and total time taken by the object during the whole journey .

Total distance covered :-

= 1st distance + 2nd distance

= (35 + 50) m

= 85 metres

Total time taken :-

= 1st time + 2nd time

= (4 + 10) sec

= 10 seconds

Now, we can calculate the average speed by putting values in the formula .

Average speed :-

= Total distance/Total time

= 85/10

= 8.5 m/s