Question

an object travelling at 35.3 m/s experience a displacement of 346 m after uniform accelaration for 8.9s. What was its accelaration?

Answer 1

Answer:

Acceleration of the object = 0.78 m/s²

Explanation:

Initial Velocity of the object = u  = 35.3 m/s

Displacement of the object = s = 346 m

Uniform acceleration = a = ?

Time for which object is accelerated = 8.9s

From the equation -

s = (u * t) + (1/2 * a * t²)

346 = 35.3 * 8.9 + 1/2 * a * (8.9)²

346 = 35 * 9 + 1/2 * a * (9)²

346 = 314 + 1/2 * a * 81

346 - 314 = 81/2 * a

32 * 2/81 = a

a = 64/81 m/s²

a = 7/9 m/s²

a = 0.78 m/s²