An object travels 10 km at a speed of 100m/s and another 10 km at 50 m/s.The average speed over the whole distance is?
Answers
Answered by
87
for first 10 km
s1 = 10 km
speed = 100 m/s = 100 x 18/5 =360 km/h
time = distance/speed =10/360 =1/36 h
for second 10 km
s2 = 10 km
speed =50 m/s = 50 x 18/5 = 180 km/h
time = distance/speed =10/180 = 1/18 h
now,
average speed =total distance/total time
total distance = 10+10 = 20 km
total time =1/36 +1/18 =1/12 h
avg. speed = 20/ 1/12 =240 km/h
240 x 5/18 = 200/3 m/s
s1 = 10 km
speed = 100 m/s = 100 x 18/5 =360 km/h
time = distance/speed =10/360 =1/36 h
for second 10 km
s2 = 10 km
speed =50 m/s = 50 x 18/5 = 180 km/h
time = distance/speed =10/180 = 1/18 h
now,
average speed =total distance/total time
total distance = 10+10 = 20 km
total time =1/36 +1/18 =1/12 h
avg. speed = 20/ 1/12 =240 km/h
240 x 5/18 = 200/3 m/s
Answered by
103
time to travel the first 10 km = 10000/100 = 100 seconds.
time to travel next 10 km = 10000/50 =200 sec.
average speed = total distance / total duration = 20000 / 300 m/s
= 66.667 m/s
time to travel next 10 km = 10000/50 =200 sec.
average speed = total distance / total duration = 20000 / 300 m/s
= 66.667 m/s
Similar questions