an object travels 10m in the 3rd second and 28m in 6th secondof its motion. what distance will be covered by in the 10th second
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Answered by
5
as there is a increase of 6 m in every second in 10 second the object must have covered 52 m
RaoHitesh:
no 34 is right answer pls retry
Answered by
2
a+2d=10
a+5d=28
fnow we have to
a+9d=?
from eqn 1 and 2
3d=18
d=6
a+12=10
a=-2
so a+9d=-2+9*6=52
so answer should be 52
what i have done above is -
since
Sn=u+a/2*(2n-1)
since a is constat
and u as well.
n varies so Sn become an AP.
a+5d=28
fnow we have to
a+9d=?
from eqn 1 and 2
3d=18
d=6
a+12=10
a=-2
so a+9d=-2+9*6=52
so answer should be 52
what i have done above is -
since
Sn=u+a/2*(2n-1)
since a is constat
and u as well.
n varies so Sn become an AP.
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