Question

An object travels 16 m in 4 s and than another 26 m in 2 s what is the average speed of the object

Answer 1

The total distance covered = 16 m + 26 m = 42 m.

Total time taken = 4 s + 2 s = 6 s.

Average speed, $\sf v_{av} = \dfrac { Total \; distance }{ Total \; time }$

• $\sf v_{av} = \dfrac { 42 }{ 6 }$

• $\sf v_{av} = 7 \; m/s$