Question

An object travels 16 m in 4 s and then another 16 m in 2 s.what is the average speed

of the object?​

Answer 1

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• Average speed = 5.33 m/s.

$\large{\underline{\sf{\red{SOLUTION}}}}$

$\leadsto$ Total distance covered by the object = 16 + 16 = 32 m.

$\leadsto$ Total time taken, t = 4 + 2 = 6 sec.

$\leadsto$ Average speed, $\sf V_{avg} \: = \: \dfrac {S}{t} \: = \: \dfrac {32}{6} \: = \: 5.33 \: m/s.$

Answer 2

Explanation: average speed = total distance / total time

Total distance travell = 16 + 16 = 32 m

Total time = 4 +2 = 6s

Average speed = 32/6 = 5.33m/s

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