Question

an object Travels 16 metre in 4 second and then another 16 metres in 2 second and next 16metre in 5 second
1) comment about it speech / motion.
2)find the average speed. ​

Answer 1

Given

• Case 1 : 16 m in 4 sec
• Case 2 : 16 m in 2 sec
• Case 3 : 16 m in 5 sec

To Find

• Type of motion
• AVG speed

Solution

☯ AVG speed = Total distance/Total time

• Similarly for the type of motion, we consider it to be uniform of it covers equal distance in equal intervals of time and accepted motion if it covers unequal distances in equal interval of time

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✭ According to the Question :

➞ AVG speed = Total distance/Total time

➞ AVG speed = (16+16+16)/(4+2+5)

➞ AVG speed = 48/11

➞ AVG speed = 4.36 m/s

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• Here, the body accelerates from case 1 to case 2 & then decelerates.

Answer 2

Solution:

• Average speed is the ratio of total distance covered by the body to the total time taken by the body to cover this distance.
• Here, an object travels unequal distance in equal intervals of time, irrespective of the interval of time, so it's accelerated motion.

Total distance = 16 + 16 = 32m

Total time = 4 + 2 = 6s

Average speed = Total distance travelled/ Total time taken

Average speed = 32/6

Average speed = 16/3

Average speed = $5\frac{1}{3}$

Average speed = 5.33m/s.