Question

an object Travels 16 metre in 4 seconds and then another 16 metre in 2 seconds what is the average speed of an object

Answer 1

the average speed= total distance /total time
32/6
16/3
5whole1/3
5.333

Answer 2

Given :-

According to the question, it is given that the object travels 16m in 4s in the first way and then 16m in 2s in the second way.

To Find :-

Here, we have to find the average speed of the given object.

Solution :-

Here,

$\sf{We~ Have,} \begin{cases} \sf{ s_{1} = 16m, ~~ t_{1} = 4s; }\\ \sf{ s_{2} = 16m, ~~ t_{2} = 2s.} \end{cases}$

Now, we know that, to find the average speed of an object, we can,

$\sf{Average ~Speed = \frac{Total ~Distance~ Travelled}{Total~ Time ~Taken}}$

Thus, by applying the formula on the given distance & time, we can,

$\to \sf{ V_{av} = \frac{s_{1} + s_{2}}{t_{1} + t_{2}}}$

$\to\sf{ \frac{(16 + 16)m}{(4 + 2)s} }$

$\to \sf{ \frac{32}{6}~m/s }$

$\to \bf \red{5.33~m/s}$

∴ Hence, the average speed of the object will be 5.33 m/s.

Thanks!!! :D