Science, asked by sourabhbaghelji9, 3 months ago

An object travels 16 min 4 sec and then another 32 meter in
in 4 sec. What is the average speed
of the object.​

Answers

Answered by ar9519282985
0

AnsweThe average speed of the object is 5.33 m/s.

The average speed of the object is 5.33 m/s.Explanation:

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}=

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= time

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 m

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 seconds

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 m

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 seconds

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 secondsAverage speed of an object =\frac{D 1+D 2}{T 1+T 2}=

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 secondsAverage speed of an object =\frac{D 1+D 2}{T 1+T 2}= T1+T2

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 secondsAverage speed of an object =\frac{D 1+D 2}{T 1+T 2}= T1+T2D1+D2

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 secondsAverage speed of an object =\frac{D 1+D 2}{T 1+T 2}= T1+T2D1+D2

The average speed of the object is 5.33 m/s.Explanation:Velocity V = \bold{=\frac{\text {distance}}{t i m e}}= timedistance Distance traveled by an object in part 1, D1 = 16 mTime taken by an object (in part 1), T1 = 4 secondsDistance traveled by an object in part 2, D2 = 16 mTime taken by in part 2, T2 = 2 secondsAverage speed of an object =\frac{D 1+D 2}{T 1+T 2}= T1+T2D1+D2 = 16 + 16 / 4 + 2 = 5.33 m/s

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