Question

An object travels 16m in 45 sec and then another 16m in 25sec. What is the average speed of the object

Answer 1

Explanation:

Total distance = 16m + 16m = 32m

Total time = 4s + 2s = 6s

Average speed = Total distance / Total time

                       = 32/6

                       = 5.33 m/s

Answer 2

Explanation:

An object travels 16 meters in 4 seconds and then another 16 meters in 2 seconds. What is the average speed of the object?

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In case of determining average speed ( in terms of Physics ) , it is given by total distance travelled by the moving object divided by total time taken to travel the total distance ( as Speed = Distance ÷ Time )

Now in the above case :-

Total Distance Covered = 16 + 16 = 32 m

Total Time Taken to Travel 32m = 4 + 2 = 6 s

Thus The Average Speed of the Moving Object = 32 ÷ 6 = 5.33 m/s

This is different from the Mathematical Average of Speeds

Speed of the object in first case = 16 ÷4 = 4 m / s

Speed of the object in second case = 16 ÷ 2 = 8 m / s .

Mathematical Average of Speeds = ( 4 + 8 ) ÷ 2 = 12 / 2

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Calculate the two speeds separately. Then add them together and divide by 2.

Like this, let,

D1=16 | T1=4 & D2=16 | T2=2, where D and T stand for Distance and Time respectively, 1 and 2 being the instances.

The formula would be,

Average speed=((D1/T1)+(D2/T2))/2 ,i.e,

Average speed= ((16/4)+(16/2))/2 ,i.e,

Average speed= (4+8)/2 = 12/2 = 6 m/s

Do not forget to take into account the important fact that all values must be in the same corresponding unit

To convert m/s into km/h simply multiply the value by 18/5 and to convert km/h to m/s multiply by 5/18.

The general formula is thus,

Average speed of n instances = ((D1/T1)+(D2/T2)+…+(Dn/Tn))/n

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