An object travels 16m in 45 sec and then another 16m in 25sec. What is the average speed of the object
Answers
Explanation:
Total distance = 16m + 16m = 32m
Total time = 4s + 2s = 6s
Average speed = Total distance / Total time
= 32/6
= 5.33 m/s
Explanation:
An object travels 16 meters in 4 seconds and then another 16 meters in 2 seconds. What is the average speed of the object?
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In case of determining average speed ( in terms of Physics ) , it is given by total distance travelled by the moving object divided by total time taken to travel the total distance ( as Speed = Distance ÷ Time )
Now in the above case :-
Total Distance Covered = 16 + 16 = 32 m
Total Time Taken to Travel 32m = 4 + 2 = 6 s
Thus The Average Speed of the Moving Object = 32 ÷ 6 = 5.33 m/s
This is different from the Mathematical Average of Speeds
Speed of the object in first case = 16 ÷4 = 4 m / s
Speed of the object in second case = 16 ÷ 2 = 8 m / s .
Mathematical Average of Speeds = ( 4 + 8 ) ÷ 2 = 12 / 2
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Calculate the two speeds separately. Then add them together and divide by 2.
Like this, let,
D1=16 | T1=4 & D2=16 | T2=2, where D and T stand for Distance and Time respectively, 1 and 2 being the instances.
The formula would be,
Average speed=((D1/T1)+(D2/T2))/2 ,i.e,
Average speed= ((16/4)+(16/2))/2 ,i.e,
Average speed= (4+8)/2 = 12/2 = 6 m/s
Do not forget to take into account the important fact that all values must be in the same corresponding unit
To convert m/s into km/h simply multiply the value by 18/5 and to convert km/h to m/s multiply by 5/18.
The general formula is thus,
Average speed of n instances = ((D1/T1)+(D2/T2)+…+(Dn/Tn))/n
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