Question

an object Travels 18 m in 4 seconds and next 18 m in 2 seconds calculate the speed of the object

Answer 1

Given that,
S1 = 18m
T1 = 4sec
S2 = 18m
T2 = 2sec
Average velocity = Total distance / Total Time
= 18 + 18 / 4 + 2
= 36 / 6 = 6m/sec.

Answer 2

Average Speed
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Here in this question two different time intervals are given so we have to find average speed of this motion,

So, firstly

In 1st Part of journey

Distance = 18m

Time taken = 4 second

So speed(S),

S = Distance/time

= 18/4 m/s

In second part of the journey

Distance = 18 m

Time taken = 2 second

so,
Speed = 18/2 m/s

= 9 m/s



Now,

Average speed = { speed of the first journey + speed of the 2nd jorney }/2

= {18/4 + 9}/2 m/s

= {(18+36)/4}/2 m/s

=54/2 m/s

= 27 m/s

so speed will be 27 m/sec.