Question

An object travels 18m in 2s and then another 18 in 6s. What is the average speed of the object?

Answer 1

$\bigstar$ Given

An object travels 18 m in 2 s and then another 18 m in 6 s

$\bigstar$ To Find

The average speed of the object

$\bigstar$ Solution

We know that

$\red{\sf \longrightarrow s=\dfrac{d}{t}}$

Here

• s = average speed
• d = total distance
• t = total time

According to the question

We are asked to find the average speed of the object

Given that

An object travels 18 m in 2 s and then another 18 m in 6 s

Hence

• d = 18 m + 18 m = 36 m
• t = 2 s + 6 s = 8 s

Substituting the values

We get

$\orange{\sf \longrightarrow s=\dfrac{36}{8} \ m/s}$

On further simplification

We get

$\pink{\sf \longrightarrow s=4.5 \ m/s}$

Therefore

$\checkmark$ Average speed  = 4.5 m/s

Answer 2

Given:-

• An object travels 18 m in 2 s and then another 18 m in 6 s

To Find:-

• The average speed of the object

Solution:-

Formula :

$\orange{\sf ➜ s=\dfrac{d}{t}}$

Where,

• s = average speed

• d = total distance

• t = total time

Now,

$\implies$ d = 18 m + 18 m = 36 m

$\implies$ t = 2 s + 6 s = 8 s

Substituting the values,

$\sf \implies s=\dfrac{36}{8} \ m/s$

Therefore,

$\pink{\sf{\boxed{\underline{ → Avg \: Speed =4.5 \ m/s}}}}$

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