Question

An object travels 18m in 5s and then another 18m in 2s. What is it average speed?​

Answer 1

1 st situation

distance = 18 m

time taken = 5 s

2 nd situation

distance = 18 m

time taken = 2 s

total distance = 18 + 18 = 36 m

total time taken = 5 + 2 = 7 s

$average \: speed = \frac{total \: distance \: }{total \: time} \\ \\ average \: speed = \frac{36}{7} \\ \\ average \: speed = 5.14 \: m {s}^{ - 1}$