Question

An object travels 18m in 6s and then another 15 m in 5s. What is the avarage speed of the object?

Answer 1

GiveN : An object travels 18m in 6s and then another 15 m in 5s.

To FinD : The average speed of the object.

In order to calculate the average speed firstly, we need to calculate total distance and total time taken.

➝ Total distance = (18 + 15) m

➝ Total distance = 33 m

Now, we have to find time taken. Time taken in both cases will be different.

➝ Total time = t₁ + t₂

➝ Total time = (6 + 5) s

➝ Total time = 11 s

As per the question, we have to calculate the average speed. Average speed is defined as total distance covered divided by total time.

➝ Average speed = Total distance ÷ Total time

➝ Average speed = 33 m ÷ 11 s

➝ Average speed = 3 m/s

Henceforth,

• The average speed of the object is 3 m/s. $\:$

Answer 2

Answer:-

Distances travelled

• 18m
• 15m

Times Taken

• 6s
• 5s

We know that

$\boxed{\sf Average\:Speed=\dfrac{Total\:Distance}{Total\:Time}}$

$\\ \sf\longmapsto Average\:Speed=\dfrac{18+15}{6+5}$

$\\ \sf\longmapsto Average\:Speed=\dfrac{33}{11}$

$\\ \sf\longmapsto Average\:speed=3m/s$