Question

an object travels 20 m in 2 s and then another 160 m in 4 s. what is the average velocity of the object after 6 sec? It's urgent​

Answer 1

Explanation:

From s=ut+12at2

in first 2s,s=20m

∴20=0+12a(2)2=2a,a=10m/s2

Velocity at the end of 2s is v=u+at=0+10×2=20m/s.

In next 4s,

s=vt+12a't2

∴160=20×4+12a'(4)2 or 80=8a' or a'=10m/s2

It shows that acceleration is uniform.

From v=u+at

v=0+10×7=70m/s.

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