English, asked by Voldemortjiiii, 9 months ago

An object travels 20 m in 4 seconds and then another 20 minutes 2 seconds then what is the average speed of the object.

Answers

Answered by Anonymous

Answer :D

1st distance covered = d₁ = 20 m

1st time taken = t₁ = 4 seconds.

2nd distance covered = d₂ = 20 m

2nd time taken = t₂ = 2 seconds.

As we know that,

⇒ Av. speed = Total distance/Total time

Putting all values :

⇒ Av. speed = (d₁ + d₂)/(t₁ + t₂)

⇒ Av. speed = (20 + 20)/(4 + 2)

⇒ Av. speed = 40/6

⇒ Av. speed = 6.67 m/s

Therefore,

Average speed of object = 6.67 m/s

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An object travels 20 m in 4 seconds and then another 20 minutes 2 seconds then what is the average speed of the object.​

Answers

Answer :D

1st distance covered = d₁ = 20 m

1st time taken = t₁ = 4 seconds.

2nd distance covered = d₂ = 20 m

2nd time taken = t₂ = 2 seconds.

As we know that,

⇒ Av. speed = Total distance/Total time

Putting all values :

⇒ Av. speed = (d₁ + d₂)/(t₁ + t₂)

⇒ Av. speed = (20 + 20)/(4 + 2)

⇒ Av. speed = 40/6

⇒ Av. speed = 6.67 m/s

Therefore,

Average speed of object = 6.67 m/s

Answer :D

1st distance covered = d₁ = 20 m

1st time taken = t₁ = 4 seconds.

2nd distance covered = d₂ = 20 m

2nd time taken = t₂ = 2 seconds.

As we know that,

⇒ Av. speed = Total distance/Total time

Putting all values :

⇒ Av. speed = (d₁ + d₂)/(t₁ + t₂)

⇒ Av. speed = (20 + 20)/(4 + 2)

⇒ Av. speed = 40/6

⇒ Av. speed = 6.67 m/s

An object travels 20 m in 4 seconds and then another 20 minutes 2 seconds then what is the average speed of the object.