An object travels 20 m in 4 seconds and then another 20 minutes 2 seconds then what is the average speed of the object.
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Answered by
1
Answer :D
1st distance covered = d₁ = 20 m
1st time taken = t₁ = 4 seconds.
2nd distance covered = d₂ = 20 m
2nd time taken = t₂ = 2 seconds.
As we know that,
⇒ Av. speed = Total distance/Total time
Putting all values :
⇒ Av. speed = (d₁ + d₂)/(t₁ + t₂)
⇒ Av. speed = (20 + 20)/(4 + 2)
⇒ Av. speed = 40/6
⇒ Av. speed = 6.67 m/s
Therefore,
Average speed of object = 6.67 m/s
Answered by
1
Answer :D
1st distance covered = d₁ = 20 m
1st time taken = t₁ = 4 seconds.
2nd distance covered = d₂ = 20 m
2nd time taken = t₂ = 2 seconds.
As we know that,
⇒ Av. speed = Total distance/Total time
Putting all values :
⇒ Av. speed = (d₁ + d₂)/(t₁ + t₂)
⇒ Av. speed = (20 + 20)/(4 + 2)
⇒ Av. speed = 40/6
⇒ Av. speed = 6.67 m/s
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