English, asked by Voldemortisnotgoingb, 10 months ago

An object travels 20 m in 4 seconds and then another 20 minutes 2 seconds then what is the average speed of the object.

Answers

Answered by Anonymous

Answer :D

1st distance covered = d₁ = 20 m

1st distance covered = d₁ = 20 m1st time taken = t₁ = 4 seconds.

1st distance covered = d₁ = 20 m1st time taken = t₁ = 4 seconds.2nd distance covered = d₂ = 20 m

1st distance covered = d₁ = 20 m1st time taken = t₁ = 4 seconds.2nd distance covered = d₂ = 20 m2nd time taken = t₂ = 2 seconds.

1st distance covered = d₁ = 20 m1st time taken = t₁ = 4 seconds.2nd distance covered = d₂ = 20 m2nd time taken = t₂ = 2 seconds.As we know that,

1st distance covered = d₁ = 20 m1st time taken = t₁ = 4 seconds.2nd distance covered = d₂ = 20 m2nd time taken = t₂ = 2 seconds.As we know that,⇒ Av. speed = Total distance/Total time

1st distance covered = d₁ = 20 m1st time taken = t₁ = 4 seconds.2nd distance covered = d₂ = 20 m2nd time taken = t₂ = 2 seconds.As we know that,⇒ Av. speed = Total distance/Total timePutting all values :

1st distance covered = d₁ = 20 m1st time taken = t₁ = 4 seconds.2nd distance covered = d₂ = 20 m2nd time taken = t₂ = 2 seconds.As we know that,⇒ Av. speed = Total distance/Total timePutting all values :⇒ Av. speed = (d₁ + d₂)/(t₁ + t₂)

1st distance covered = d₁ = 20 m1st time taken = t₁ = 4 seconds.2nd distance covered = d₂ = 20 m2nd time taken = t₂ = 2 seconds.As we know that,⇒ Av. speed = Total distance/Total timePutting all values :⇒ Av. speed = (d₁ + d₂)/(t₁ + t₂)⇒ Av. speed = (20 + 20)/(4 + 2)

1st distance covered = d₁ = 20 m1st time taken = t₁ = 4 seconds.2nd distance covered = d₂ = 20 m2nd time taken = t₂ = 2 seconds.As we know that,⇒ Av. speed = Total distance/Total timePutting all values :⇒ Av. speed = (d₁ + d₂)/(t₁ + t₂)⇒ Av. speed = (20 + 20)/(4 + 2)⇒ Av. speed = 40/6

1st distance covered = d₁ = 20 m1st time taken = t₁ = 4 seconds.2nd distance covered = d₂ = 20 m2nd time taken = t₂ = 2 seconds.As we know that,⇒ Av. speed = Total distance/Total timePutting all values :⇒ Av. speed = (d₁ + d₂)/(t₁ + t₂)⇒ Av. speed = (20 + 20)/(4 + 2)⇒ Av. speed = 40/6⇒ Av. speed = 6.67 m/s

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Answered by sgstheboss262

In the first part of distance covered,

Distance = 20 m

Time = 4 s

Second part of distance,

Distance = 20 m

Time = 2 s

Average speed = total distance divided by total time

Total distance = 20 + 20 = 40 m

Total time = 6 s

Therefore,

Average speed = $\frac{40}{6} = \frac{20}{3}$ m/s

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