Question

An object travels 20m in 3 s and the another 30m in 4s What
the average speed of the object?​

Answer 1

Given :–

• D₁ = 20m
• T₁ = 3s
• D₂ = 30m
• T₂ = 4s

To Find :–

• Average speed of the object.

Solution :–

First, we need to find the total distance.

So,

Total distance (D) = D₁ + D₂

⟹ 20m + 30m

⟹ 50m

Now, we need to find the total time taken.

So,

Total time taken (T) = T₁ + T₂

⟹ 3s + 4s

⟹ 7s

Now, we need to find the average speed of the object,

So,

Average speed = $\dfrac{Total \: Distance}{Total \: Time \: Taken}$

⟹ $\dfrac{D}{T}$

• D = 50m
• T = 7s

⟹ $\dfrac{50}{7}$

⟹ 7.14286 m/s

Hence,

The average speed is 7.14286 m/s.

Answer 2

GivEn:-

• An object travels 20m in 3 s

• another it travel 30m in 4s

To find:-

• average speed of the object?

SoluTion:-

☯ Here, we have to find average speed of the object.

$\star\;{\underline{\boxed{\bf{\purple{Average\;Speed = \dfrac{Total\;Distance}{Total\;Time}}}}}}$

GivEn that,

An object travels 20m in 3 s and the another 30m in 4s.

Therefore,

☯ Total distance travelled by Object = 20m + 30m = 50m

☯ Total time taken by Object = 3m + 4m = 7s

★ ${\underline{\sf{\red{Now,\;Put\;the\;value\;in\;formula\;-}}}}$

$\dashrightarrow\sf \dfrac{Total\; Distance}{Total\;time}$

$\dashrightarrow\sf \dfrac{50}{7}$

$\dashrightarrow\bf \pink{7.14\;ms^{-1}}\;\bigstar$

$\sf\dag\; \underline{Hence,\; Average\;speed\;of\;the\;object\;is\;7.14\;ms^{-1}}$

$\rule{200}{4}$

Additional Information:-

• Speed is a scalar quantity.

• Dimensional formula of speed is $\sf \dfrac{[L]}{[T]} = LT^{-1}$

• Speed is rate of change of distance per unit time whereas, Velocity is rate of change of displacement per unit time.

• Both speed and velocity are measured in $\sf ms^{-1}$