Question

An object travels 25 M in 5 Sec and then object travels 25 M in 3 Sec. What is the
average speed of the object?​

Answer 1

$\mathfrak{\large{\underline{\underline{Given:-}}}}$

In 1 st case :-

Distance travelled = 25 m

Time taken = 5 sec

In 2 nd case :-

Distance travelled = 25 m

Time taken = 3 sec

$\mathfrak{\large{\underline{\underline{</strong><strong>T</strong><strong>o</strong><strong> </strong><strong>f</strong><strong>ind</strong><strong>:-}}}}$

Average speed of object = ?

$\mathfrak{\large{\underline{\underline{</strong><strong>S</strong><strong>o</strong><strong>l</strong><strong>u</strong><strong>t</strong><strong>i</strong><strong>o</strong><strong>n</strong><strong>:-}}}}$

★ $\boxed{\sf{</strong><strong>A</strong><strong>v</strong><strong>e</strong><strong>r</strong><strong>a</strong><strong>g</strong><strong>e</strong><strong> </strong><strong>speed</strong><strong> </strong><strong> </strong><strong>=</strong><strong> </strong><strong>\frac{total \: distance \: travelled}{total \: time \: taken} </strong><strong>}}$

$\implies$ $\bold{ </strong><strong> </strong><strong>=</strong><strong> \frac{25 + 25}{5 + 3} </strong><strong> </strong><strong>}$

$\implies$ $\bold{</strong><strong>= \frac{100}{8} m</strong><strong> </strong><strong>/</strong><strong>sec</strong><strong>}$

$\implies$ $\bold{</strong><strong> = \frac{25}{2} m</strong><strong>/</strong><strong>sec</strong><strong>}$

hence , average speed = $\</strong><strong> \frac{25}{2} </strong><strong>m</strong><strong>/</strong><strong>sec</strong><strong>$

Answer 2

Heya mate here is your answer

#In first case :-

Distance travelled , s =25M

Time taken ,t=5sec

#In Second case :-

Distance travelled ,s=25M

Time taken , t=3sec

We know that ,

#Average speed =Total distance covered

_______________________

Total time taken

Average speed=25+25

________

5+3

Average speed = 25+25

_______

8

Average speed=50

____

8

Average speed=25

____m/s

4

Hope it helps

please mark brainliest ✌️✌️