Question

An object travels 27m in 5 s and then another 28m in 4 s . The average speed of the object is??​

Answer 1

Answer:

Answer =6.1m/s

Explanation:

Avg.speed =v1+v2/t1+t2

=27+28/5+4=55/9

=6.11m/s

Answer 2

Given : An object travels 27 m in 5 sec and then another 28 m in 4s.

To find : The average speed of the object.

solution : we know,

average speed = total distance/total/time taken

here the object travels 27 m in 5 sec and then another 28 m in 4s.

then total distance = 27m + 28m = 55 m

total time taken = 5 sec + 4 sec = 9 sec

The average speed = 55m/9sec

= 6.11 m/s

Therefore the average speed of the object is 6.11 m/s.

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