Question

An object travels 3 m due east then turns left and travels 5 km due north and finally turns right and travels 9m towards east . calculate
the displacement..
plz abs this question​

Answer 1

The displacement is defined as the shortest distance between the initial point and the final point.

• In such questions, the displacement can be calculated by making the use of vectors.

       Here we are given that the object first travels 3m in the east direction,

       the vector for this will be 3i.

       Then, it travels 5m towards the north, the vector for this will be 5j.

      Finally, it travels 9m towards the east, the vector for this will be 9i.

∴ Displacement = 3i + 5j + 9i

                          =12i + 5j

The resultant can be given as $\sqrt{12^{2} + 5^{2} }$ = $\sqrt{144 + 25}$

                                                                  = $\sqrt{169}$

                                                                   = 13 m

The displacement of the particle will be 13 m.

                   

Answer 2

The displacement is defined as the shortest distance between the initial point and the final point.  

• In such questions, the displacement can be calculated by making the use of vectors.
• Here we are given that the object first travels 3m in the east direction,  the vector for this will be 3i.  

     Then, it travels 5m towards the north, the vector for this will be 5j.  

     Finally, it travels 9m towards the east, the vector for this will be 9i.  

∴ Displacement

$= 3i + 5j + 9i$

 $=12i + 5j$

The resultant can be given as:

$\sqrt{12^{2} +5^{2} } =\sqrt{144+25} \\=\sqrt{169} \\=13m$  

Hence, The displacement of the particle will be $13 m.$