Question

An object travels 32m in 8s and then as another 32m in 4s . what is the average speed of the object

Answer 1

Answer:

5.3 m/s

Explanation:

average speed=total speed ÷total time=

32+32/8+4=64/12=5.3m/s

Answer 2

Answer:

The average speed of the object is $\frac{16}{3} ms^-^1$.

Explanation:

The average speed is defined as the total distance traveled by an object in a particular time interval. As the average speed is a scalar quantity, it is only represented by the magnitude and does not have any direction. It is given as,

$V_a_v_g=\frac{x}{t}$           (1)

Where,

Vavg= average speed

x=total distance traveled by the object

t=total time taken

The values given in the question are,

x₁=32m

t₁=8s

x₂=32

t₂=4s

We can also write equation (1) as,

$V_a_v_g=\frac{x_1+x_2}{t_1+t_2}$          (2)

By substituting the required values in equation (2) we get;

$V_a_v_g=\frac{32+32}{8+4}=\frac{64}{12}=\frac{16}{3} ms^-^1$

Hence, the average speed of the object is $\frac{16}{3} ms^-^1$.