Question

an object travels 40m in 5second and then another80m in 5second what is the average speed of the object (i) 12m/s (ii) 6m/s (iii) 2m/s (iv) 0m/s​

Answer 1

GIVEN :-

• Distance 1 (d1) = 40 m
• Time 1 (t1) = 5 seconds
• Distance 2 (d2) = 80 m
• Time 2 (t2) = 5 seconds

TO FIND :-

• The Average speed.

SOLUTION :-

$\dag \: \boxed{ \red{ \bf \: average \: \: speed = \: \dfrac{ total \: distance}{total \: time} }} \\ \\ \mapsto \sf \dfrac{ \:d_{1} + d_{2}}{t_{1} + t_{2}} \\ \\ \mapsto \sf \: \dfrac{80 + 40}{5 + 5} \\ \\ \mapsto \sf \: \cancel{\frac{120}{10} } \\ \\ \mapsto \underline{ \boxed{ \red{ \sf \: average \: \: speed \: = 12 \: ms ^{ - 1} }}}$

Hence the Average speed is 12 m/s.

HENCE OPTION (III) ✔

ADDITIONAL INFORMATION :-

☛ Average speed :- The ratio of Total distance travelled by an object to the total time taken is known as average speed of the object.

$\dag \: \boxed{ \red{ \bf \: average \: \: speed = \: \dfrac{ total \: distance}{total \: time} }} \\ \\ \mapsto \sf \dfrac{ \:d_{1} + d_{2}}{t_{1} + t_{2}}$

☛ Velocity :- Velocity of an object is defined as the distance travelled by an object in unit time in a particular direction .

$\dag \: \boxed{ \red{ \bf \: Velocity = \: \dfrac{ Displacement}{ time} }}$

Answer 2

★ Given -

• Distance 1 (D1) = 40m
• Time 1 (T1) = 5sec
• Distance 2 (D2) = 80m
• Time (T2) = 5sec

★ To Find -

• Average velocity of object

★ Solution -

We know Formula For Average Velocity,

$✓ \: \frac{</strong><strong>T</strong><strong>otal \: </strong><strong>D</strong><strong>istance}{</strong><strong>T</strong><strong>otal \: </strong><strong>T</strong><strong>ime}$

Applying Values,

$⟶ \frac{(40 + 80)}{(5 + 5)}$

$⟶ \frac{120}{10}$

$⟶\frac{\cancel{120}}{\cancel{10}}$

$⟶12 {m</strong><strong>/</strong><strong>s}^{ - 1}$

⛬ Average Velocity Of given Object is 12m/s-¹