An object travels at constant speed around a circle of radius 1.0 m in 1.0 s.What is the magnitude of its acceleration???
2pi square
pi square
4 pi square
Answers
Answer:
2pi square
Explanation:
area of circle=2π(r)square
radius=1m
= 2π(1) square
=2π
velocity= distance / time
= 2π/1
= 2π
acceleration= velocity / time
2π/1
= 2π
Answer:
2π²
Explanation:
According to Newton's 2nd law, the acceleration a is proportional to the internet pressure F and inversely proportional to the item's mass m . So a way to calculate the value of acceleration? By analogy - the value of the acceleration is proportional to the value of this pressure. Magnitude of acceleration = Rate of alternate of withinside the value of speed + Rate of converting the path of motion.
If you understand that acceleration is constant, you may remedy for it with out time when you have the preliminary and very last speed of the item in addition to the quantity of displacement. Use the system v^2=u^2+2as wherein v is the very last speed, u is the preliminary speed, a is acceleration, and s is displacement.
region of circle=2πr²
radius=1m
= 2π(1) ²
speed= distance / time
= 2π/1
= 2π
acceleration= speed / time
2π/1
= 2π
some related links
https://brainly.in/question/1177864
https://brainly.in/question/37884136
#SPJ2