Question

an object travels with intial velocity 3km/h and changes to 6km/h in a 5 second , and force applied on object 5 dyne. find the mass of an object?
[Hint: 1 dyne= 10*5 newton]

Answer 1

Answer:

Acceleration refers to the change in velocity with respect to time.

According to the question, Initial velocity (u) is 3 km/hr, Final Velocity (v) is 6 km/hr and time taken for change is 5 seconds. Hence the acceleration of the object is:

$\implies a = \dfrac{v-u}{t}\\\\\\\implies a = \dfrac{6 - 3}{5}\\\\\\\implies a = \dfrac{3}{5} = \boxed{\bf{0.6 \:\:m/s^2}}$

Also, we are given that the force applied on the object is 5 dyne, where 1 dyne is equal to 10⁵ N. Hence the force of 5 dyne in terms of Newton is:

⇒ F = 5 × 10⁵ N

We know that, Force = Mass × Acceleration. Hence the value of mass in terms of Force and Acceleration is given as:

⇒ Mass = Force / Acceleration

⇒ Mass = ( 5 × 10⁵ ) / 0.6

⇒ Mass = 8.3 × 10⁵ kg

Hence the mass of the object is 8.3 × 10⁵ kg

Answer 2

Answer:

Question :-

• An object travels with intial velocity 3km/h and changes to 6km/h in a 5 second , and force applied on object 5 dyne. find the mass of an object?

Given :-

• An object travels with intial velocity 3km/h and changes to 6km/h in a 5 second , and force applied on object 5 dyne.

Find Out :-

• Find the mass of an object?

Solution :-

✭ In case of acceleration :-

As we know that :

✯ $\red{ \boxed{\sf{v =\: u + at}}}$ ✯

We have :

• Final Velocity = 6 m/s
• Initial Velocity = 3 m/s
• Time = 5 seconds

So, according to the question or ATQ :-

$\longrightarrow \sf 6 =\: 3 + a(5)$

$\longrightarrow \sf 6 - 3 =\: 5a$

$\longrightarrow \sf 3 =\: 5a$

$\longrightarrow \sf \dfrac{3}{5} =\: a$

$\longrightarrow \sf\boxed{\bold{\red{a =\: 0.6\: m/s^2}}}$

✭ In case of mass of an object :-

We have :

• Force = 5 × 10⁵ N
• Acceleration = 0.6 m/s²

As we know that :

☆ $\red{ \boxed{\sf{F =\: ma}}}$ ☆

So, according to the question or ATQ :-

$\longrightarrow \sf 5 \times 10^5 =\: m \times 0.6$

$\longrightarrow \sf \dfrac{5 \times 10^5}{0.6} =\: m$

$\longrightarrow$ ${\small{\bold{\purple{\underline{m =\: 8.3 \times 10^5\: Kg}}}}}$

Henceforth, the mass of an object is 8.3 × 10⁵ Kg .