Question

An object
ucm in size, is placed at
minion, focal
25cm infront
da can cave
length 15cm. At what distance from the
mitton would a screen be placed in order
obtain a shatp image ? Find the nature
to
and
the nature and the size of the image
?​

Answer 1

distance from the  Mitty would ha screen be placed is 50 cm

Explanation:

1/f=1/v-1/u

1/15=1/v-1/25

1/v=1/15+1/25

1/v=1/50

v=50 cm

m=v/u

=50/(-25)

=-2