Question

an object under goes an acceleration of10m/s starting from rest .find the distance traveled in 5 second​

Answer 1

$\Large\underline{\underline{\red{\sf \purple{\maltese}\:\: Given :- }}}$

$\implies\textsf{ Object has an acceleration of \sf 10m/s^2 . }\\\implies \textsf{Object stated from rest .}\\\implies\textsf{ It travelled for 5 sec. }$

$\Large\underline{\underline{\red{\sf \purple{\maltese}\:\: To \ Find :- }}}$

$\implies\textsf{ Distance travelled in 5 seconds .}$

$\Large\underline{\underline{\red{\sf \purple{\maltese}\:\: Answer :- }}}$

Since the object started from rest , its initial Velocity will be 0m/s . Acceleration of the object is 10m/s² . Let's use second equation of motion .

$\underline{\boldsymbol{\purple{ Using \ second \ equation \ of \ motion :- }}}$

$\sf:\implies \pink{ s = ut + \dfrac{1}{2}at^2}\\\\\sf:\implies s = (0m/s)(5s) + \dfrac{1}{2}\times 10m/s^2 \times (5s)^2 \\\\\sf:\implies s = 0 + 5 \times 25 m \\\\\sf:\implies s = 0 + 125 m \\\\\sf:\implies\boxed{\pink{\mathfrak{ Distance_{(for \ 5 \ s )} = 125 m }}}$

$\underline{\blue{\sf Hence \ the \ Distance \ travelled\ is \ \textsf{\textbf{125m }}. }}$